What is the answer to 2^x-1+2^x+1=2 ?

The answer to 2^x-1+2^x+1=2 is x=0

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2^x-1+2^x+1=2

2^{x} - 1 + 2^{x} + 1 = 2

x = 0

Solution steps

2^{x} - 1 + 2^{x} + 1 = 2

Group like terms

2^{x} + 2^{x} - 1 + 1 = 2

Add similar elements:

2^{x} + 2^{x} = 2 \cdot 2^{x}

2 \cdot 2^{x} - 1 + 1 = 2

- 1 + 1 = 0

2 \cdot 2^{x} = 2

Divide both sides by

2

2^{x} = 1

Apply exponent rules

x ln (2) = ln (1)

Solve

x ln (2) = ln (1) : x = 0

x = 0

7^{x - 1} + 7^{x} = 2744

\frac{1}{8} = \frac{4}{2 ^{\frac{t}{7}}}

5^{3 x - 1} = 25

3^{x} = \frac{14}{25}

3^{3 x + 1} = 9^{x + 4}