What is the answer to 5^{5-x}=2^{5-x} ?

The answer to 5^{5-x}=2^{5-x} is x=(5ln(5)-5ln(2))/(ln(5)-ln(2))

Solve for x: 5^{5-x}=2^{5-x}

The solution is x=(5ln(5)-5ln(2))/(ln(5)-ln(2))

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5^{5 - x} = 2^{5 - x}

x = \frac{5 ln ( 5 ) - 5 ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 5

Solution steps

5^{5 - x} = 2^{5 - x}

Apply exponent rules

(5 - x) ln (5) = (5 - x) ln (2)

Solve

(5 - x) ln (5) = (5 - x) ln (2) : x = \frac{5 ln ( 5 ) - 5 ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{5 ln ( 5 ) - 5 ln ( 2 )}{ln ( 5 ) - ln ( 2 )}

5^{3 x - 1} = 3^{1 - 2 x}

3^{2 x - 1} - 3^{x} = 18

2^{x} - 3 = 8

e^{x} = 3

2^{2 x + 3} + 2^{x + 3} = 1 + 2^{x}

What is the answer to 5^{5-x}=2^{5-x} ?
The answer to 5^{5-x}=2^{5-x} is x=(5ln(5)-5ln(2))/(ln(5)-ln(2))
Solve for x: 5^{5-x}=2^{5-x}
The solution is x=(5ln(5)-5ln(2))/(ln(5)-ln(2))