What is the answer to 3^{x+1}= 1/((27^{x-3))} ?

The answer to 3^{x+1}= 1/((27^{x-3))} is x=2

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3^{x+1}= 1/((27^{x-3))}

3^{x + 1} = \frac{1}{( 2 7 ^{x - 3} )}

x = 2

Solution steps

3^{x + 1} = \frac{1}{( 2 7 ^{x - 3} )}

Apply exponent rules

x + 1 = 3 (- x + 3)

Solve

x + 1 = 3 (- x + 3) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

5^{x} - 24 = \frac{25}{5 ^{x}}

4 (3^{2 x}) = e^{x}

3^{x + 2} = 3^{1 - x} - 26

3^{x} = 9

2^{n} + 3^{m} = a^{k}

What is the answer to 3^{x+1}= 1/((27^{x-3))} ?
The answer to 3^{x+1}= 1/((27^{x-3))} is x=2
Solve for x: 3^{x+1}= 1/((27^{x-3))}
The solution is x=2