What is the answer to 8^x=16^{-1}*sqrt(32^x) ?

The answer to 8^x=16^{-1}*sqrt(32^x) is x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8^x=16^{-1}*sqrt(32^x)

8^{x} = 1 6^{- 1} \cdot 3 2^{x}

x = - 8

Solution steps

8^{x} = 1 6^{- 1} 3 2^{x}

Apply exponent rules

3 x = \frac{5}{2} x - 4

Solve

3 x = \frac{5}{2} x - 4 : x = - 8

x = - 8

\frac{1}{64} = (\frac{1}{2})^{n - 1}

3^{2 x + 1} = 5^{2 x + 1}

1 0^{x} = - 2

6^{5 x} = 27

100000 = 1 0^{x}

What is the answer to 8^x=16^{-1}*sqrt(32^x) ?
The answer to 8^x=16^{-1}*sqrt(32^x) is x=-8
Solve for x: 8^x=16^{-1}*sqrt(32^x)
The solution is x=-8