What is the answer to 8^x-1=16 ?

The answer to 8^x-1=16 is x=(ln(17))/(3ln(2))

Solve for x: 8^x-1=16

The solution is x=(ln(17))/(3ln(2))

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8^{x} - 1 = 16

x = \frac{ln ( 17 )}{3 ln ( 2 )}

Decimal Notation

x = 1.36248 \dots

Solution steps

8^{x} - 1 = 16

Move

1

to the right side

8^{x} = 17

Apply exponent rules

x ln (8) = ln (17)

Solve

x ln (8) = ln (17) : x = \frac{ln ( 17 )}{3 ln ( 2 )}

x = \frac{ln ( 17 )}{3 ln ( 2 )}

42 e^{\frac{x}{4}} = 32

8^{7 x + 9} = 2^{3 x + 6}

4^{x + 10} = 3^{- 10 x}

x, (d^{3} + 1) (d - 1)^{3} = e^{x}

3 x - 1 = 2^{x}