What is the answer to (((2^{1-2x}))/((2^{x+3))})^3=4 ?

The answer to (((2^{1-2x}))/((2^{x+3))})^3=4 is x=-8/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(((2^{1-2x}))/((2^{x+3))})^3=4

(\frac{( 2 ^{1 - 2 x} )}{( 2 ^{x + 3} )})^{3} = 4

x = - \frac{8}{9}

Decimal Notation

x = - 0.88888 \dots

Solution steps

(\frac{( 2 ^{1 - 2 x} )}{( 2 ^{x + 3} )})^{3} = 4

Apply exponent rules

(- 3 x - 2) \cdot 3 = 2

Solve

(- 3 x - 2) \cdot 3 = 2 : x = - \frac{8}{9}

x = - \frac{8}{9}

Verify Solutions:

x = - \frac{8}{9}

True

The solution is

x = - \frac{8}{9}

y, \frac{( 2 ^{y} - 1 )}{( 2 ^{y} + 1 )} = x

3^{x} = 171

2^{1 + x} + 2^{1 - x} = 5

x, \frac{( 9 ^{x} - 1 )}{( 3 ^{y} + 2 )} = 81

(\frac{1}{5})^{3 + x} = (\frac{1}{25})^{4}

What is the answer to (((2^{1-2x}))/((2^{x+3))})^3=4 ?
The answer to (((2^{1-2x}))/((2^{x+3))})^3=4 is x=-8/9
Solve for x: (((2^{1-2x}))/((2^{x+3))})^3=4
The solution is x=-8/9