What is the answer to solvefor p,(2^{x-2}*1)/2 =p(x)^{x-3} ?

The answer to solvefor p,(2^{x-2}*1)/2 =p(x)^{x-3} is p=(2^{x-3})/(x^{x-3)}

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solvefor p,(2^{x-2}*1)/2 =p(x)^{x-3}

solve for

p, \frac{2 ^{x - 2} \cdot 1}{2} = p (x)^{x - 3}

p = \frac{2 ^{x - 3}}{x ^{x - 3}}

Solution steps

\frac{2 ^{x - 2} \cdot 1}{2} = p x^{x - 3}

Switch sides

p x^{x - 3} = \frac{2 ^{x - 2} \cdot 1}{2}

Simplify

\frac{2 ^{x - 2} \cdot 1}{2} : 2^{x - 3}

p x^{x - 3} = 2^{x - 3}

Divide both sides by

x^{x - 3}

p = \frac{2 ^{x - 3}}{x ^{x - 3}}

3 = 0.5 \cdot 1.0 5^{x}

5^{x^{2} + 3 x} = 1

4^{x - 5} = 9

3^{3 \cdot l o g_{3} (x)} = 27

6 \cdot 2^{x} = 64 + 2 \cdot 2^{x}

What is the answer to solvefor p,(2^{x-2}*1)/2 =p(x)^{x-3} ?
The answer to solvefor p,(2^{x-2}*1)/2 =p(x)^{x-3} is p=(2^{x-3})/(x^{x-3)}