What is the answer to (3^{x/2}+3)/(3^{x/2)}=4 ?

The answer to (3^{x/2}+3)/(3^{x/2)}=4 is x=0

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(3^{x/2}+3)/(3^{x/2)}=4

\frac{3 ^{\frac{x}{2}} + 3}{3 ^{\frac{x}{2}}} = 4

x = 0

Solution steps

\frac{3 ^{\frac{x}{2}} + 3}{3 ^{\frac{x}{2}}} = 4

Apply exponent rules

((3^{x})^{0.5} + 3) (3^{x})^{- 0.5} = 4

Rewrite the equation with

3^{x} = u

(u^{0.5} + 3) (u)^{- 0.5} = 4

Solve

(u^{0.5} + 3) u^{- 0.5} = 4 : u = 1

u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 1 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

2^{t} = 0

1 0^{c} = 10000

x, d^{2} - 3 d + 2 = \frac{1}{( 1 + e ^{x} )}

(2^{x})^{2} - 2 x + 1 = 2^{16} - 4 x

4^{x + 2} - 2 (4^{x + 1}) = 2^{4 x}

What is the answer to (3^{x/2}+3)/(3^{x/2)}=4 ?
The answer to (3^{x/2}+3)/(3^{x/2)}=4 is x=0
Solve for x: (3^{x/2}+3)/(3^{x/2)}=4
The solution is x=0