What is the answer to 256^{2x-16}=(1/128)^{20-2x} ?

The answer to 256^{2x-16}=(1/128)^{20-2x} is x=-6

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256^{2x-16}=(1/128)^{20-2x}

25 6^{2 x - 16} = (\frac{1}{128})^{20 - 2 x}

x = - 6

Solution steps

25 6^{2 x - 16} = (\frac{1}{128})^{20 - 2 x}

Apply exponent rules

8 (2 x - 16) = - 7 (20 - 2 x)

Solve

8 (2 x - 16) = - 7 (20 - 2 x) : x = - 6

x = - 6

\frac{2 ^{8}}{3 ^{8}} = (\frac{- 2}{3})^{n - 1}

3^{x} - 1 = 0

\frac{( 64 \cdot 4 ^{3 n} + 4 \cdot 4 ^{3 n + 3} )}{( 16 \cdot 4 ^{2 n} - 1 6 ^{n} )} = \frac{256}{3}

4^{x + 2} + 4^{x} = 1088

2^{x} = 100

What is the answer to 256^{2x-16}=(1/128)^{20-2x} ?
The answer to 256^{2x-16}=(1/128)^{20-2x} is x=-6
Solve for x: 256^{2x-16}=(1/128)^{20-2x}
The solution is x=-6