What is the answer to 3^{-2}*0.3^4*0.3^n=3 ?

The answer to 3^{-2}*0.3^4*0.3^n=3 is n=(3ln(3))/(ln(0.3))-4

Solve for n: 3^{-2}*0.3^4*0.3^n=3

The solution is n=(3ln(3))/(ln(0.3))-4

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3^{- 2} \cdot 0. 3^{4} \cdot 0. 3^{n} = 3

n = \frac{3 ln ( 3 )}{ln ( 0.3 )} - 4

Decimal Notation

n = - 6.73746 \dots

Solution steps

3^{- 2} \cdot 0. 3^{4} \cdot 0. 3^{n} = 3

Apply exponent rules

(n + 4) ln (0.3) = ln (27)

Solve

(n + 4) ln (0.3) = ln (27) : n = \frac{3 ln ( 3 )}{ln ( 0.3 )} - 4

n = \frac{3 ln ( 3 )}{ln ( 0.3 )} - 4

\frac{2 ^{t}}{3.8} = 20

(9^{7 x - 2}) = 3^{x + 6}

b, x^{y} + y^{x} + x^{4} + a^{b} = 1

5^{x + 3} = (\frac{1}{125})^{x}

1 0^{p} = 40

What is the answer to 3^{-2}*0.3^4*0.3^n=3 ?
The answer to 3^{-2}*0.3^4*0.3^n=3 is n=(3ln(3))/(ln(0.3))-4
Solve for n: 3^{-2}*0.3^4*0.3^n=3
The solution is n=(3ln(3))/(ln(0.3))-4