What is (1/3)^{-2/5}*96^{-2/5} ?

The solution to (1/3)^{-2/5}*96^{-2/5} is 3^{2/5}*1/(4*3^{2/5)}

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simplify (1/3)^{-2/5}*96^{-2/5}

simplify

(\frac{1}{3})^{- \frac{2}{5}} \cdot 9 6^{- \frac{2}{5}}

3^{\frac{2}{5}} \cdot \frac{1}{4 \cdot 3 ^{\frac{2}{5}}}

Solution steps

(\frac{1}{3})^{- \frac{2}{5}} \cdot 9 6^{- \frac{2}{5}}

(\frac{1}{3})^{- \frac{2}{5}} = 3^{\frac{2}{5}}

= 3^{\frac{2}{5}} \cdot 9 6^{- \frac{2}{5}}

9 6^{- \frac{2}{5}} = \frac{1}{4 \cdot 3 ^{\frac{2}{5}}}

= 3^{\frac{2}{5}} \cdot \frac{1}{4 \cdot 3 ^{\frac{2}{5}}}

- 6 x - 2 > 10

\frac{( 3 k ) ^{3}}{2 k ^{- 10}}

\frac{2 ^{5}}{5}

\frac{x - 4}{14} + \frac{3 x - 12}{18} = 2

2 \geq 1

What is (1/3)^{-2/5}*96^{-2/5} ?
The solution to (1/3)^{-2/5}*96^{-2/5} is 3^{2/5}*1/(4*3^{2/5)}