What is the answer to 2^{x+1}+2^{x+2}=48 ?

The answer to 2^{x+1}+2^{x+2}=48 is x=3

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2^{x+1}+2^{x+2}=48

2^{x + 1} + 2^{x + 2} = 48

x = 3

Solution steps

2^{x + 1} + 2^{x + 2} = 48

Factor

2^{x + 1} + 2^{x + 2} : 3 \cdot 2^{x + 1}

3 \cdot 2^{x + 1} = 48

Divide both sides by

3

2^{x + 1} = 16

Apply exponent rules

x + 1 = 4

Solve

x + 1 = 4 : x = 3

x = 3

3.34 = 3.2 1^{n}

2^{k} \cdot 7^{d} = 392

9 \cdot 3^{x} = (27)^{2 x - 5}

7^{4 x} - 8 \cdot 7^{4 x} + 7 = 0

a, \frac{x ^{6}}{x ^{a}} = x^{8}

What is the answer to 2^{x+1}+2^{x+2}=48 ?
The answer to 2^{x+1}+2^{x+2}=48 is x=3
Solve for x: 2^{x+1}+2^{x+2}=48
The solution is x=3