What is the answer to 6^{x+2}=17^{-5x} ?

The answer to 6^{x+2}=17^{-5x} is x=-(2ln(6))/(ln(6)+5ln(17))

Solve for x: 6^{x+2}=17^{-5x}

The solution is x=-(2ln(6))/(ln(6)+5ln(17))

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6^{x + 2} = 1 7^{- 5 x}

x = - \frac{2 ln ( 6 )}{ln ( 6 ) + 5 ln ( 17 )}

Decimal Notation

x = - 0.22456 \dots

Solution steps

6^{x + 2} = 1 7^{- 5 x}

Apply exponent rules

(x + 2) ln (6) = - 5 x ln (17)

Solve

(x + 2) ln (6) = - 5 x ln (17) : x = - \frac{2 ln ( 6 )}{ln ( 6 ) + 5 ln ( 17 )}

x = - \frac{2 ln ( 6 )}{ln ( 6 ) + 5 ln ( 17 )}

1.1 1^{x} = \frac{7}{4}

1 0^{a} = 0.1

500000 = 65000 (1.07)^{x}

32768 = 2^{x}

5^{x + 1} = 25

What is the answer to 6^{x+2}=17^{-5x} ?
The answer to 6^{x+2}=17^{-5x} is x=-(2ln(6))/(ln(6)+5ln(17))
Solve for x: 6^{x+2}=17^{-5x}
The solution is x=-(2ln(6))/(ln(6)+5ln(17))