What is the answer to 5^{7x-4}=(1/625)^{x+6} ?

The answer to 5^{7x-4}=(1/625)^{x+6} is x=-20/11

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5^{7x-4}=(1/625)^{x+6}

5^{7 x - 4} = (\frac{1}{625})^{x + 6}

x = - \frac{20}{11}

Decimal Notation

x = - 1.81818 \dots

Solution steps

5^{7 x - 4} = (\frac{1}{625})^{x + 6}

Apply exponent rules

7 x - 4 = - 4 (x + 6)

Solve

7 x - 4 = - 4 (x + 6) : x = - \frac{20}{11}

x = - \frac{20}{11}

5^{x} = - 3

2^{x - 1} = (2)^{x}

(16)^{3 n} = 8^{5}

1 + x = e^{x}

- e^{2 x} + 3 x + 4 = 0

What is the answer to 5^{7x-4}=(1/625)^{x+6} ?
The answer to 5^{7x-4}=(1/625)^{x+6} is x=-20/11
Solve for x: 5^{7x-4}=(1/625)^{x+6}
The solution is x=-20/11