What is the answer to 3^x-1+3^x-2+3^x-3=13 ?

The answer to 3^x-1+3^x-2+3^x-3=13 is x=(ln(19/3))/(ln(3))

Solve for x: 3^x-1+3^x-2+3^x-3=13

The solution is x=(ln(19/3))/(ln(3))

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3^{x} - 1 + 3^{x} - 2 + 3^{x} - 3 = 13

x = \frac{ln ( \frac{19}{3} )}{ln ( 3 )}

Decimal Notation

x = 1.68014 \dots

Solution steps

3^{x} - 1 + 3^{x} - 2 + 3^{x} - 3 = 13

Group like terms

3^{x} + 3^{x} + 3^{x} - 1 - 2 - 3 = 13

Add similar elements:

3^{x} + 3^{x} + 3^{x} = 3 \cdot 3^{x}

3 \cdot 3^{x} - 1 - 2 - 3 = 13

Subtract the numbers:

- 1 - 2 - 3 = - 6

3 \cdot 3^{x} - 6 = 13

Move

6

to the right side

3 \cdot 3^{x} = 19

Divide both sides by

3

3^{x} = \frac{19}{3}

Apply exponent rules

x ln (3) = ln (\frac{19}{3})

Solve

x ln (3) = ln (\frac{19}{3}) : x = \frac{ln ( \frac{19}{3} )}{ln ( 3 )}

x = \frac{ln ( \frac{19}{3} )}{ln ( 3 )}

e^{x^{2} - 3 x} = 0

3^{x} + 3^{2 x} = 3^{3 x}

a (21) = 12000 (1 + (\frac{0.095}{12}))^{12 x^{21}}

4^{x} + 1 + 4^{x} = 24

3^{x + 2} - 3^{x - 2} = 2160

What is the answer to 3^x-1+3^x-2+3^x-3=13 ?
The answer to 3^x-1+3^x-2+3^x-3=13 is x=(ln(19/3))/(ln(3))
Solve for x: 3^x-1+3^x-2+3^x-3=13
The solution is x=(ln(19/3))/(ln(3))