What is the answer to (2^x)^2-3*2^x+2=0 ?

The answer to (2^x)^2-3*2^x+2=0 is x=1,x=0

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(2^x)^2-3*2^x+2=0

(2^{x})^{2} - 3 \cdot 2^{x} + 2 = 0

x = 1, x = 0

Solution steps

(2^{x})^{2} - 3 \cdot 2^{x} + 2 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} - 3 u + 2 = 0

Solve

u^{2} - 3 u + 2 = 0 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 2 : x = 1

Solve

2^{x} = 1 : x = 0

x = 1, x = 0

x, 5^{x + 1} + 5^{1 - x} = 2 t

2^{x} = x^{3}

2^{1 - x} = \frac{1}{81}

3^{n} = 9 n

1 0^{1} - x = 6^{x}

What is the answer to (2^x)^2-3*2^x+2=0 ?
The answer to (2^x)^2-3*2^x+2=0 is x=1,x=0
Solve for x: (2^x)^2-3*2^x+2=0
The solution is x=1,x=0