What is the answer to (1/(2^{x-4)})-(1/(2^{x-2)})=3 ?

The answer to (1/(2^{x-4)})-(1/(2^{x-2)})=3 is x=2

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(1/(2^{x-4)})-(1/(2^{x-2)})=3

(\frac{1}{2 ^{x - 4}}) - (\frac{1}{2 ^{x - 2}}) = 3

x = 2

Solution steps

(\frac{1}{2 ^{x - 4}}) - (\frac{1}{2 ^{x - 2}}) = 3

Apply exponent rules

- x = - 2

Solve

- x = - 2 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

4^{2} x + 8 = 3 (8^{x})

4^{x} = 64

4^{2 x + 1} + 7 (4^{x}) - 15 = 0

\frac{1}{3} = 2^{x}

lo g_{4} (2^{4 x}) = 2^{l o g_{2} (4)}

What is the answer to (1/(2^{x-4)})-(1/(2^{x-2)})=3 ?
The answer to (1/(2^{x-4)})-(1/(2^{x-2)})=3 is x=2
Solve for x: (1/(2^{x-4)})-(1/(2^{x-2)})=3
The solution is x=2