en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x+1}=4^{2x}

Solution

2^{x + 1} = 4^{2 x}

Solution

x = \frac{1}{3}

+1

Decimal Notation

x = 0.33333 \dots

Solution steps

2^{x + 1} = 4^{2 x}

Apply exponent rules

x + 1 = 4 x

Solve

x + 1 = 4 x : x = \frac{1}{3}

x = \frac{1}{3}

Popular Examples

4^{x} = \frac{1}{32}

3^x+3^{x+3}-3^{x-1}=249

3^{x} + 3^{x + 3} - 3^{x - 1} = 249

5 \cdot 2^{x} = 2 \cdot 4^{x} + 2

2^{3 - 2 x} = 32

log_{3}(2^x+1)=2

lo g_{3} (2^{x} + 1) = 2

Frequently Asked Questions (FAQ)

What is the answer to 2^{x+1}=4^{2x} ?
The answer to 2^{x+1}=4^{2x} is x= 1/3
Solve for x: 2^{x+1}=4^{2x}
The solution is x= 1/3