What is the answer to 3^{x-1}=(1/2)^{x+3} ?

The answer to 3^{x-1}=(1/2)^{x+3} is x=(ln(3/8))/(ln(6))

Solve for x: 3^{x-1}=(1/2)^{x+3}

The solution is x=(ln(3/8))/(ln(6))

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3^{x - 1} = (\frac{1}{2})^{x + 3}

x = \frac{ln ( \frac{3}{8} )}{ln ( 6 )}

Decimal Notation

x = - 0.54741 \dots

Solution steps

3^{x - 1} = (\frac{1}{2})^{x + 3}

Apply exponent rules

(x - 1) ln (3) = (x + 3) ln (\frac{1}{2})

Solve

(x - 1) ln (3) = (x + 3) ln (\frac{1}{2}) : x = \frac{ln ( \frac{3}{8} )}{ln ( 6 )}

x = \frac{ln ( \frac{3}{8} )}{ln ( 6 )}

\frac{- 32}{243} = (\frac{- 2}{3})^{2 n + 1}

a, \frac{( x ^{2 a} )}{( x ^{3} )} = x^{3}

2^{x} = \frac{1}{64}

4^{3 x + 2} = 3^{5 x - 4}

5^{t} + 3 (5^{t - 1}) = 400

What is the answer to 3^{x-1}=(1/2)^{x+3} ?
The answer to 3^{x-1}=(1/2)^{x+3} is x=(ln(3/8))/(ln(6))
Solve for x: 3^{x-1}=(1/2)^{x+3}
The solution is x=(ln(3/8))/(ln(6))