What are the solutions to the equation 3x^2-42x-5=0 ?

The solutions to the equation 3x^2-42x-5=0 are x=(21+2sqrt(114))/3 ,x=(21-2sqrt(114))/3

Find the zeros of 3x^2-42x-5=0

The zeros of 3x^2-42x-5=0 are x=(21+2sqrt(114))/3 ,x=(21-2sqrt(114))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 42 x - 5 = 0

x = \frac{21 + 2 114}{3}, x = \frac{21 - 2 114}{3}

Decimal Notation

x = 14.11805 \dots, x = - 0.11805 \dots

Solution steps

3 x^{2} - 42 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 42)^{2} - 4 \cdot 3 (- 5) = 4114

x_{1, 2} = \frac{- ( - 42 ) \pm 4 114}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 42 ) + 4 114}{2 \cdot 3}, x_{2} = \frac{- ( - 42 ) - 4 114}{2 \cdot 3}

x = \frac{- ( - 42 ) + 4 114}{2 \cdot 3} : \frac{21 + 2 114}{3}

x = \frac{- ( - 42 ) - 4 114}{2 \cdot 3} : \frac{21 - 2 114}{3}

The solutions to the quadratic equation are:

x = \frac{21 + 2 114}{3}, x = \frac{21 - 2 114}{3}

(x + 5) (x - 5)

(x - 2 + 3 i) (x - 2 - 3 i)

\frac{2}{3} - 3

y^{2} + 2 y - 24

4 y - 6 y + 9 y = - 2

What are the solutions to the equation 3x^2-42x-5=0 ?
The solutions to the equation 3x^2-42x-5=0 are x=(21+2sqrt(114))/3 ,x=(21-2sqrt(114))/3
Find the zeros of 3x^2-42x-5=0
The zeros of 3x^2-42x-5=0 are x=(21+2sqrt(114))/3 ,x=(21-2sqrt(114))/3