What is the answer to (1/3)^{2x-3}=3^{1-x} ?

The answer to (1/3)^{2x-3}=3^{1-x} is x=2

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(1/3)^{2x-3}=3^{1-x}

(\frac{1}{3})^{2 x - 3} = 3^{1 - x}

x = 2

Solution steps

(\frac{1}{3})^{2 x - 3} = 3^{1 - x}

Apply exponent rules

- (2 x - 3) = 1 - x

Solve

- (2 x - 3) = 1 - x : x = 2

x = 2

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\frac{1}{( 3 ^{- 2 x + 2} )} = 81

1 6^{p} + 4^{p - 1} = \frac{1}{4 ^{3}}

74 = 1 0^{2.37 x}

t, x^{4 a} = b^{t}

What is the answer to (1/3)^{2x-3}=3^{1-x} ?
The answer to (1/3)^{2x-3}=3^{1-x} is x=2
Solve for x: (1/3)^{2x-3}=3^{1-x}
The solution is x=2