What is the answer to solvefor a,1=(e^{-a})/b ?

The answer to solvefor a,1=(e^{-a})/b is a=-ln(b)

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solvefor a,1=(e^{-a})/b

solve for

a, 1 = \frac{e ^{- a}}{b}

a = - ln (b)

Solution steps

1 = \frac{e ^{- a}}{b}

Multiply both sides by

b

1 \cdot b = \frac{e ^{- a}}{b} b

Simplify

b = e^{- a}

Apply exponent rules

ln (b) = - a

Solve

ln (b) = - a : a = - ln (b)

a = - ln (b)

1.0 4^{x} = 5

2^{x} = 5^{x + 1}

\frac{5 ^{x} 0. 8 ^{x - 1}}{x} = 500

2. 4^{x} = 8^{x}

(k + 1) 2^{k} = 32

What is the answer to solvefor a,1=(e^{-a})/b ?
The answer to solvefor a,1=(e^{-a})/b is a=-ln(b)