What are the solutions to the equation 4x^2+1=4x ?

The solutions to the equation 4x^2+1=4x are x= 1/2

Find the zeros of 4x^2+1=4x

The zeros of 4x^2+1=4x are x= 1/2

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4 x^{2} + 1 = 4 x

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

4 x^{2} + 1 = 4 x

Move

4 x

to the left side

4 x^{2} + 1 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

- \frac{1}{2} + \frac{5}{2}

2 x + 5 = 3 x - 1

3 n - 8 = 32

20 = 10 x

\frac{1}{\frac{1}{10}}

What are the solutions to the equation 4x^2+1=4x ?
The solutions to the equation 4x^2+1=4x are x= 1/2
Find the zeros of 4x^2+1=4x
The zeros of 4x^2+1=4x are x= 1/2