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Popular >

solvefor n,2=t+t^n

Solution

solve for

n, 2 = t + t^{n}

Solution

n = \frac{ln ( 2 - t )}{ln ( t )}

Solution steps

2 = t + t^{n}

Switch sides

t + t^{n} = 2

Move

t

to the right side

t^{n} = 2 - t

Apply exponent rules

n ln (t) = ln (2 - t)

Solve

n ln (t) = ln (2 - t) : n = \frac{ln ( 2 - t )}{ln ( t )}

n = \frac{ln ( 2 - t )}{ln ( t )}

Popular Examples

((2^x*3^x))/((12^x))= 1/8

\frac{( 2 ^{x} \cdot 3 ^{x} )}{( 1 2 ^{x} )} = \frac{1}{8}

32 = 8^{x}

4^{3x-1}=5^{x+1}

4^{3 x - 1} = 5^{x + 1}

1 0^{x} = 3 - 2 x

solvefor n,p(x+1)-p=x^n solve for

n, p (x + 1) - p = x^{n}

Frequently Asked Questions (FAQ)

What is the answer to solvefor n,2=t+t^n ?
The answer to solvefor n,2=t+t^n is n=(ln(2-t))/(ln(t))