What is the answer to 3^{40}+3^{40}+3^x=3^{41} ?

The answer to 3^{40}+3^{40}+3^x=3^{41} is x=40

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{40}+3^{40}+3^x=3^{41}

3^{40} + 3^{40} + 3^{x} = 3^{41}

x = 40

Solution steps

3^{40} + 3^{40} + 3^{x} = 3^{41}

Add similar elements:

3^{40} + 3^{40} = 2 \cdot 3^{40}

2 \cdot 3^{40} + 3^{x} = 3^{41}

Move

2 \cdot 3^{40}

to the right side

3^{x} = 3^{41} - 2 \cdot 3^{40}

Apply exponent rules

x = 40

5^{x + 1} = 5^{x} + 100

9 e^{\frac{- x}{2}} + 12 e^{\frac{- x}{6}} = 0

8^{3} x - 1 = 7^{x} + 2

2^{2 x + 1} - 33 (2^{x - 1}) + 4 = 0

5^{x - 3} + 12 5^{x + 3} = 78125

What is the answer to 3^{40}+3^{40}+3^x=3^{41} ?
The answer to 3^{40}+3^{40}+3^x=3^{41} is x=40
Solve for x: 3^{40}+3^{40}+3^x=3^{41}
The solution is x=40