What is the answer to solvefor x,y^x-y^y=-26 ?

The answer to solvefor x,y^x-y^y=-26 is x=(ln(-26+y^y))/(ln(y))

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solvefor x,y^x-y^y=-26

solve for

x, y^{x} - y^{y} = - 26

x = \frac{ln ( - 26 + y ^{y} )}{ln ( y )}

Solution steps

y^{x} - y^{y} = - 26

Move

y^{y}

to the right side

y^{x} = - 26 + y^{y}

Apply exponent rules

x ln (y) = ln (- 26 + y^{y})

Solve

x ln (y) = ln (- 26 + y^{y}) : x = \frac{ln ( - 26 + y ^{y} )}{ln ( y )}

x = \frac{ln ( - 26 + y ^{y} )}{ln ( y )}

x^{(l o g_{10} (x)) + 2} = 1 0^{(l o g_{10} (x)) + 2}

(- 3)^{x} = 87

x, (2^{2})^{x} - (3^{2})^{y} = 55

x, ((3^{x})^{5})^{y} = 225

(\frac{1}{2})^{a + 1} + (\frac{1}{2})^{a + 3} + (\frac{1}{2})^{a + 5} = 42

What is the answer to solvefor x,y^x-y^y=-26 ?
The answer to solvefor x,y^x-y^y=-26 is x=(ln(-26+y^y))/(ln(y))