What is the answer to 3^{3-x}*2^{5x}=3^{x+5}*2^{3x} ?

The answer to 3^{3-x}*2^{5x}=3^{x+5}*2^{3x} is x=(log_{2}(3))/(-log_{2)(3)+1}

Solve for x: 3^{3-x}*2^{5x}=3^{x+5}*2^{3x}

The solution is x=(log_{2}(3))/(-log_{2)(3)+1}

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3^{3 - x} \cdot 2^{5 x} = 3^{x + 5} \cdot 2^{3 x}

x = \frac{lo g _{2} ( 3 )}{- lo g _{2} ( 3 ) + 1}

Decimal Notation

x = - 2.70951 \dots

Solution steps

3^{3 - x} \cdot 2^{5 x} = 3^{x + 5} \cdot 2^{3 x}

Apply exponent rules

lo g_{2} (3) (3 - x) + 5 x = lo g_{2} (3) (x + 5) + 3 x

Solve

lo g_{2} (3) (3 - x) + 5 x = lo g_{2} (3) (x + 5) + 3 x : x = \frac{lo g _{2} ( 3 )}{- lo g _{2} ( 3 ) + 1}

x = \frac{lo g _{2} ( 3 )}{- lo g _{2} ( 3 ) + 1}

5^{3} \cdot 5^{x} - 2 = 2 5^{2}

4^{x - 3 x - 16} = 16

x^{x} = 0.2

9^{x} + 2 = 720 + x

2^{2 x + 3} - 57 = 65 (2^{x} - 1)

What is the answer to 3^{3-x}*2^{5x}=3^{x+5}*2^{3x} ?
The answer to 3^{3-x}*2^{5x}=3^{x+5}*2^{3x} is x=(log_{2}(3))/(-log_{2)(3)+1}
Solve for x: 3^{3-x}*2^{5x}=3^{x+5}*2^{3x}
The solution is x=(log_{2}(3))/(-log_{2)(3)+1}