What is the answer to 2^{2x+1}-15(2^x)-8=0 ?

The answer to 2^{2x+1}-15(2^x)-8=0 is x=3

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2^{2x+1}-15(2^x)-8=0

2^{2 x + 1} - 15 (2^{x}) - 8 = 0

x = 3

Solution steps

2^{2 x + 1} - 15 (2^{x}) - 8 = 0

Apply exponent rules

(2^{x})^{2} \cdot 2^{1} - 15 \cdot 2^{x} - 8 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} \cdot 2^{1} - 15 u - 8 = 0

Solve

u^{2} \cdot 2^{1} - 15 u - 8 = 0 : u = 8, u = - \frac{1}{2}

u = 8, u = - \frac{1}{2}

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 8 : x = 3

Solve

2^{x} = - \frac{1}{2} :

No Solution for

x \in R

x = 3

x, (2007)^{x} + (2007)^{y} = 1

n = \frac{( 2 ^{n + 4} - 2 ^{n + 3} )}{( 2 ^{n + 4} )}

\frac{8 1 ^{2}}{( 72 9 ^{1} ) ^{- x}} = (9^{2})^{x}

2^{x - 4} = 4. 2^{x - 6}

2 = 1.0 6^{x}

What is the answer to 2^{2x+1}-15(2^x)-8=0 ?
The answer to 2^{2x+1}-15(2^x)-8=0 is x=3
Solve for x: 2^{2x+1}-15(2^x)-8=0
The solution is x=3