What is the answer to solvefor x,2^x+2^y=2^y+4^x ?

The answer to solvefor x,2^x+2^y=2^y+4^x is x=0

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solvefor x,2^x+2^y=2^y+4^x

solve for

x, 2^{x} + 2^{y} = 2^{y} + 4^{x}

x = 0

Solution steps

2^{x} + 2^{y} = 2^{y} + 4^{x}

Move

2^{y}

to the left side

2^{x} = 4^{x}

Apply exponent rules

x = 2 x

Solve

x = 2 x : x = 0

x = 0

3^{x - 3} = 2 x - 5

n, q^{2} + 9 q^{n - 3} - q^{2 n - 1} - 9 = 0

4 x^{3} \cdot e^{- 3 x} - 3 x^{4} \cdot e^{- 3 x} = 0

\frac{2 ^{x + 5}}{3 ^{x + 5}} = 0.01156

3^{x - 1} = 27

What is the answer to solvefor x,2^x+2^y=2^y+4^x ?
The answer to solvefor x,2^x+2^y=2^y+4^x is x=0