What is the answer to solvefor c,p(b^c)=0.7 ?

The answer to solvefor c,p(b^c)=0.7 is c=(ln((0.7)/p))/(ln(b))

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solvefor c,p(b^c)=0.7

solve for

c, p (b^{c}) = 0.7

c = \frac{ln ( \frac{0.7}{p} )}{ln ( b )}

Solution steps

p (b^{c}) = 0.7

Divide both sides by

p

b^{c} = \frac{0.7}{p}

Apply exponent rules

c ln (b) = ln (\frac{0.7}{p})

Solve

c ln (b) = ln (\frac{0.7}{p}) : c = \frac{ln ( \frac{0.7}{p} )}{ln ( b )}

c = \frac{ln ( \frac{0.7}{p} )}{ln ( b )}

2^{x + 3} + 2^{x + 1} = 80

- 5^{x + 1} + 8 \cdot 5^{x} = 15 \cdot 5^{- 3}

2^{x + 1} = 3^{x - 4}

5^{x} = 0.2

lo g_{2} (2 5^{x + 3} - 1) = 2 + lo g_{2} (5^{x + 3} + 1)

What is the answer to solvefor c,p(b^c)=0.7 ?
The answer to solvefor c,p(b^c)=0.7 is c=(ln((0.7)/p))/(ln(b))