What is the answer to solvefor l,y^m-6y^n+11y^l-6y=0 ?

The answer to solvefor l,y^m-6y^n+11y^l-6y=0 is l=(ln(\frac{-y^m+6y^n+6y)/(11))}{ln(y)}

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solvefor l,y^m-6y^n+11y^l-6y=0

solve for

l, y^{m} - 6 y^{n} + 11 y^{l} - 6 y = 0

l = \frac{ln ( \frac{- y ^{m} + 6 y ^{n} + 6 y}{11} )}{ln ( y )}

Solution steps

y^{m} - 6 y^{n} + 11 y^{l} - 6 y = 0

Move

y^{m}

to the right side

- 6 y^{n} + 11 y^{l} - 6 y = - y^{m}

Move

6 y^{n}

to the right side

11 y^{l} - 6 y = - y^{m} + 6 y^{n}

Move

6 y

to the right side

11 y^{l} = - y^{m} + 6 y^{n} + 6 y

Divide both sides by

11

y^{l} = \frac{- y ^{m} + 6 y ^{n} + 6 y}{11}

Apply exponent rules

l ln (y) = ln (\frac{- y ^{m} + 6 y ^{n} + 6 y}{11})

Solve

l ln (y) = ln (\frac{- y ^{m} + 6 y ^{n} + 6 y}{11}) : l = \frac{ln ( \frac{- y ^{m} + 6 y ^{n} + 6 y}{11} )}{ln ( y )}

l = \frac{ln ( \frac{- y ^{m} + 6 y ^{n} + 6 y}{11} )}{ln ( y )}

2 = (1.06)^{n}

2 7^{x} = 9

8^{3 x} = 6 4^{x + 1}

4^{n - 1} = (4)^{4}

(3^{x} + 1) - 3^{x} = 162

What is the answer to solvefor l,y^m-6y^n+11y^l-6y=0 ?
The answer to solvefor l,y^m-6y^n+11y^l-6y=0 is l=(ln(\frac{-y^m+6y^n+6y)/(11))}{ln(y)}