What is the answer to 3*2^x=15 ?

The answer to 3*2^x=15 is x=(ln(5))/(ln(2))

Solve for x: 3*2^x=15

The solution is x=(ln(5))/(ln(2))

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3 \cdot 2^{x} = 15

x = \frac{ln ( 5 )}{ln ( 2 )}

Decimal Notation

x = 2.32192 \dots

Solution steps

3 \cdot 2^{x} = 15

Divide both sides by

3

2^{x} = 5

Apply exponent rules

x ln (2) = ln (5)

Solve

x ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )}

x = \frac{ln ( 5 )}{ln ( 2 )}

(\frac{3}{4})^{1 - 3 x} = \frac{210}{27}

x, 7 7^{x} + 8 8^{y} = 6776

x, 9^{x - 1} = 24 3^{y + 2}

16 = 2^{n}

\frac{( ( 2 ) ^{3 x + 2} + ( 2 ) ^{2} )}{( ( 2 ) ^{4 x + 4} )} = 1