What is the answer to solvefor x,y^*+9y=e^{2x}7 ?

The answer to solvefor x,y^*+9y=e^{2x}7 is x=(ln((10y)/7))/(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y^*+9y=e^{2x}7

solve for

x, y^{\cdot} + 9 y = e^{2 x} 7

x = \frac{ln ( \frac{10 y}{7} )}{2}

Solution steps

y + 9 y = e^{2 x} \cdot 7

Switch sides

e^{2 x} \cdot 7 = y + 9 y

Add similar elements:

y + 9 y = 10 y

e^{2 x} \cdot 7 = 10 y

Divide both sides by

7

e^{2 x} = \frac{10 y}{7}

Apply exponent rules

2 x = ln (\frac{10 y}{7})

Solve

2 x = ln (\frac{10 y}{7}) : x = \frac{ln ( \frac{10 y}{7} )}{2}

x = \frac{ln ( \frac{10 y}{7} )}{2}

2^{x - 4} = 4^{x - 6}

2 x = 8^{x} + 4

3^{- 4 x} = 9^{6 - x}

4^{2 n + 1} - 12 = 52

2^{x} = 512

What is the answer to solvefor x,y^*+9y=e^{2x}7 ?
The answer to solvefor x,y^*+9y=e^{2x}7 is x=(ln((10y)/7))/(2)