What is the answer to solvefor x,1f*((3^{3x-1}))/9 =27 ?

The answer to solvefor x,1f*((3^{3x-1}))/9 =27 is x=(ln((729)/f))/(3ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,1f*((3^{3x-1}))/9 =27

solve for

x, 1 f \cdot \frac{( 3 ^{3 x - 1} )}{9} = 27

x = \frac{ln ( \frac{729}{f} )}{3 ln ( 3 )}

Solution steps

1 \cdot f \frac{( 3 ^{3 x - 1} )}{9} = 27

Refine

1 \cdot f \frac{3 ^{3 x - 1}}{9} : \frac{f \cdot 3 ^{3 x - 1}}{9}

\frac{f \cdot 3 ^{3 x - 1}}{9} = 27

Multiply both sides by

9

f \cdot 3^{3 x - 1} = 243

Divide both sides by

f

3^{3 x - 1} = \frac{243}{f}

Apply exponent rules

(3 x - 1) ln (3) = ln (\frac{243}{f})

Solve

(3 x - 1) ln (3) = ln (\frac{243}{f}) : x = \frac{ln ( \frac{729}{f} )}{3 ln ( 3 )}

x = \frac{ln ( \frac{729}{f} )}{3 ln ( 3 )}

3^{x} + 3^{x} - 1 = 108

(5^{x}) - (5^{x + 2}) + 125 = 0

3 = 2 7^{x}

2 \cdot 4^{x} + 4^{- x} = \frac{9}{2}

\frac{2 ^{x}}{2 ^{5}} = 1

What is the answer to solvefor x,1f*((3^{3x-1}))/9 =27 ?
The answer to solvefor x,1f*((3^{3x-1}))/9 =27 is x=(ln((729)/f))/(3ln(3))