What is the general solution for solvefor x,2u+3v=e^x(cos(y)-sin(y)) ?

The general solution for solvefor x,2u+3v=e^x(cos(y)-sin(y)) is x=ln((2u+3v)/(cos(y)-sin(y)))

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solvefor x,2u+3v=e^x(cos(y)-sin(y))

solve for

x, 2 u + 3 v = e^{x} (cos (y) - sin (y))

x = ln (\frac{2 u + 3 v}{cos ( y ) - sin ( y )})

Solution steps

2 u + 3 v = e^{x} (cos (y) - sin (y))

Switch sides

e^{x} (cos (y) - sin (y)) = 2 u + 3 v

Divide both sides by

cos (y) - sin (y)

e^{x} = \frac{2 u + 3 v}{cos ( y ) - sin ( y )}

Apply exponent rules

x = ln (\frac{2 u + 3 v}{cos ( y ) - sin ( y )})

e^{y} = 0

2^{x + 3} + 2^{x} = 72

2^{x + 3} = 4^{x - 1}

2^{x + 1} + 2^{x} - 2^{x} - 2 = 88

2 = (1.05)^{n}

What is the general solution for solvefor x,2u+3v=e^x(cos(y)-sin(y)) ?
The general solution for solvefor x,2u+3v=e^x(cos(y)-sin(y)) is x=ln((2u+3v)/(cos(y)-sin(y)))