What is the answer to 3^{2x+2}+3^{2x+1}=108 ?

The answer to 3^{2x+2}+3^{2x+1}=108 is x=1

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3^{2x+2}+3^{2x+1}=108

3^{2 x + 2} + 3^{2 x + 1} = 108

x = 1

Solution steps

3^{2 x + 2} + 3^{2 x + 1} = 108

Apply exponent rules

2 x = 2

Solve

2 x = 2 : x = 1

x = 1

4 9^{n - 1} + 6 = 7^{2 n - 1}

(125)^{x + 4} = 5

2 = (\frac{9}{8})^{t}

4^{x} - 4^{x - 1} = 48

(\frac{2}{3})^{x} \cdot (\frac{9}{8})^{x} = 2764

What is the answer to 3^{2x+2}+3^{2x+1}=108 ?
The answer to 3^{2x+2}+3^{2x+1}=108 is x=1
Solve for x: 3^{2x+2}+3^{2x+1}=108
The solution is x=1