What is the answer to solvefor x,b=a*(1+63/100)^x ?

The answer to solvefor x,b=a*(1+63/100)^x is x=(ln(b/a))/(ln(163/100))

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solvefor x,b=a*(1+63/100)^x

solve for

x, b = a \cdot (1 + \frac{63}{100})^{x}

x = \frac{ln ( \frac{b}{a} )}{ln ( \frac{163}{100} )}

Solution steps

b = a (1 + \frac{63}{100})^{x}

Switch sides

a (1 + \frac{63}{100})^{x} = b

Divide both sides by

a

(1 + \frac{63}{100})^{x} = \frac{b}{a}

Apply exponent rules

x ln (1 + \frac{63}{100}) = ln (\frac{b}{a})

Solve

x ln (1 + \frac{63}{100}) = ln (\frac{b}{a}) : x = \frac{ln ( \frac{b}{a} )}{ln ( \frac{163}{100} )}

x = \frac{ln ( \frac{b}{a} )}{ln ( \frac{163}{100} )}

3^{x} + x - 4 = 0

x^{x} = 4

x^{x} = 5

(a) lo g_{3} (1 + lo g_{3} (2^{x} - 7)) = 1

2^{x - 3} = 128

What is the answer to solvefor x,b=a*(1+63/100)^x ?
The answer to solvefor x,b=a*(1+63/100)^x is x=(ln(b/a))/(ln(163/100))