What is the answer to 2^x+1+2^x+2=48 ?

The answer to 2^x+1+2^x+2=48 is x=(ln(45/2))/(ln(2))

Solve for x: 2^x+1+2^x+2=48

The solution is x=(ln(45/2))/(ln(2))

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2^{x} + 1 + 2^{x} + 2 = 48

x = \frac{ln ( \frac{45}{2} )}{ln ( 2 )}

Decimal Notation

x = 4.49185 \dots

Solution steps

2^{x} + 1 + 2^{x} + 2 = 48

Group like terms

2^{x} + 2^{x} + 1 + 2 = 48

Add similar elements:

2^{x} + 2^{x} = 2 \cdot 2^{x}

2 \cdot 2^{x} + 1 + 2 = 48

Add the numbers:

1 + 2 = 3

2 \cdot 2^{x} + 3 = 48

Move

3

to the right side

2 \cdot 2^{x} = 45

Divide both sides by

2

2^{x} = \frac{45}{2}

Apply exponent rules

x ln (2) = ln (\frac{45}{2})

Solve

x ln (2) = ln (\frac{45}{2}) : x = \frac{ln ( \frac{45}{2} )}{ln ( 2 )}

x = \frac{ln ( \frac{45}{2} )}{ln ( 2 )}

3^{x + 7} = 9^{x + 1}

x, 3^{x} + 2^{y} = 1 + 2^{z}

4 e^{2 x} - 3 = 2

e^{x} \cdot (1 + e^{x}) = \frac{3}{4}

2187 = 2^{x}

What is the answer to 2^x+1+2^x+2=48 ?
The answer to 2^x+1+2^x+2=48 is x=(ln(45/2))/(ln(2))
Solve for x: 2^x+1+2^x+2=48
The solution is x=(ln(45/2))/(ln(2))