What is the answer to 2^n=2000 ?

The answer to 2^n=2000 is n=(ln(2000))/(ln(2))

Solve for n: 2^n=2000

The solution is n=(ln(2000))/(ln(2))

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2^{n} = 2000

n = \frac{ln ( 2000 )}{ln ( 2 )}

Decimal Notation

n = 10.96578 \dots

Solution steps

2^{n} = 2000

Apply exponent rules

n ln (2) = ln (2000)

Solve

n ln (2) = ln (2000) : n = \frac{ln ( 2000 )}{ln ( 2 )}

n = \frac{ln ( 2000 )}{ln ( 2 )}

2 5^{x} = 0.25

3^{2 x + 2} = 9^{10}

1000 = 2^{n}

9^{x - 1} - 3^{x - 2} = 8

0. 5^{6 x - 2 x} = 32