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Popular >

solvefor m,3^m-2^n=2

Solution

solve for

m, 3^{m} - 2^{n} = 2

Solution

m = \frac{ln ( 2 + 2 ^{n} )}{ln ( 3 )}

Solution steps

3^{m} - 2^{n} = 2

Move

2^{n}

to the right side

3^{m} = 2 + 2^{n}

Apply exponent rules

m ln (3) = ln (2 + 2^{n})

Solve

m ln (3) = ln (2 + 2^{n}) : m = \frac{ln ( 2 + 2 ^{n} )}{ln ( 3 )}

m = \frac{ln ( 2 + 2 ^{n} )}{ln ( 3 )}

Popular Examples

3^{x+2}+3^{-x}=10

3^{x + 2} + 3^{- x} = 10

1.2 1^{x} = 100

4^{- 6} x = 1 7^{x} + 4

4^x*4^{2x-8}=64

4^{x} \cdot 4^{2 x - 8} = 64

(\frac{1}{4})^{3 - x} = 64

Frequently Asked Questions (FAQ)

What is the answer to solvefor m,3^m-2^n=2 ?
The answer to solvefor m,3^m-2^n=2 is m=(ln(2+2^n))/(ln(3))