What is the answer to 5^{2x-1}=4^{300} ?

The answer to 5^{2x-1}=4^{300} is x=(600ln(2)+ln(5))/(2ln(5))

Solve for x: 5^{2x-1}=4^{300}

The solution is x=(600ln(2)+ln(5))/(2ln(5))

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5^{2 x - 1} = 4^{300}

x = \frac{600 ln ( 2 ) + ln ( 5 )}{2 ln ( 5 )}

Decimal Notation

x = 129.70296 \dots

Solution steps

5^{2 x - 1} = 4^{300}

Apply exponent rules

(2 x - 1) ln (5) = 300 ln (4)

Solve

(2 x - 1) ln (5) = 300 ln (4) : x = \frac{600 ln ( 2 ) + ln ( 5 )}{2 ln ( 5 )}

x = \frac{600 ln ( 2 ) + ln ( 5 )}{2 ln ( 5 )}

1 0^{p} = 0.1

202 0^{(x - 2) (2 x + 3)} = 1

x, t^{x} \cdot t^{2} = t^{10}

2700 = 2^{m} \cdot 3^{n} \cdot 5^{p}

2^{x + 5} + 2^{x + 4} + 2^{x + 3} = 112

What is the answer to 5^{2x-1}=4^{300} ?
The answer to 5^{2x-1}=4^{300} is x=(600ln(2)+ln(5))/(2ln(5))
Solve for x: 5^{2x-1}=4^{300}
The solution is x=(600ln(2)+ln(5))/(2ln(5))