What is the answer to 0.6^{x-3}=3.2^{x+4} ?

The answer to 0.6^{x-3}=3.2^{x+4} is x=(ln(22.6492416))/(ln(0.6)-ln(3.2))

Solve for x: 0.6^{x-3}=3.2^{x+4}

The solution is x=(ln(22.6492416))/(ln(0.6)-ln(3.2))

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0. 6^{x - 3} = 3. 2^{x + 4}

x = \frac{ln ( 22.6492416 )}{ln ( 0.6 ) - ln ( 3.2 )}

Decimal Notation

x = - 1.86390 \dots

Solution steps

0. 6^{x - 3} = 3. 2^{x + 4}

Apply exponent rules

(x - 3) ln (0.6) = (x + 4) ln (3.2)

Solve

(x - 3) ln (0.6) = (x + 4) ln (3.2) : x = \frac{ln ( 22.6492416 )}{ln ( 0.6 ) - ln ( 3.2 )}

x = \frac{ln ( 22.6492416 )}{ln ( 0.6 ) - ln ( 3.2 )}

3 x = e^{- x}

5^{x - 2} \cdot 2^{2 x - 3} = 135

3^{\frac{3}{( l o g _{3} ( x ) )}} = 27

4^{x + 2} = 2^{2 x + 3} + 2

(8^{2})^{0} + (8^{2})^{0} = 2^{x}

What is the answer to 0.6^{x-3}=3.2^{x+4} ?
The answer to 0.6^{x-3}=3.2^{x+4} is x=(ln(22.6492416))/(ln(0.6)-ln(3.2))
Solve for x: 0.6^{x-3}=3.2^{x+4}
The solution is x=(ln(22.6492416))/(ln(0.6)-ln(3.2))