What is the answer to 4^{x+3}=7 ?

The answer to 4^{x+3}=7 is x=(ln(7))/(2ln(2))-3

Solve for x: 4^{x+3}=7

The solution is x=(ln(7))/(2ln(2))-3

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4^{x + 3} = 7

x = \frac{ln ( 7 )}{2 ln ( 2 )} - 3

Decimal Notation

x = - 1.59632 \dots

Solution steps

4^{x + 3} = 7

Apply exponent rules

(x + 3) ln (4) = ln (7)

Solve

(x + 3) ln (4) = ln (7) : x = \frac{ln ( 7 )}{2 ln ( 2 )} - 3

x = \frac{ln ( 7 )}{2 ln ( 2 )} - 3

(6 4^{x^{2} - 2 x}) (1 6^{x - 5}) = 1

(x + 2) e^{x} = 1

t, a (t) = a_{0} \cdot e^{- 0.025 t}

3 (4^{x}) + 4^{x - 1} = 52

4^{2 x} + 12 = 2^{2 x + 3}

What is the answer to 4^{x+3}=7 ?
The answer to 4^{x+3}=7 is x=(ln(7))/(2ln(2))-3
Solve for x: 4^{x+3}=7
The solution is x=(ln(7))/(2ln(2))-3