What is the answer to 2^x-1+2^x+2^x+1=7 ?

The answer to 2^x-1+2^x+2^x+1=7 is x=(ln(7/3))/(ln(2))

Solve for x: 2^x-1+2^x+2^x+1=7

The solution is x=(ln(7/3))/(ln(2))

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2^{x} - 1 + 2^{x} + 2^{x} + 1 = 7

x = \frac{ln ( \frac{7}{3} )}{ln ( 2 )}

Decimal Notation

x = 1.22239 \dots

Solution steps

2^{x} - 1 + 2^{x} + 2^{x} + 1 = 7

Group like terms

2^{x} + 2^{x} + 2^{x} - 1 + 1 = 7

Add similar elements:

2^{x} + 2^{x} + 2^{x} = 3 \cdot 2^{x}

3 \cdot 2^{x} - 1 + 1 = 7

- 1 + 1 = 0

3 \cdot 2^{x} = 7

Divide both sides by

3

2^{x} = \frac{7}{3}

Apply exponent rules

x ln (2) = ln (\frac{7}{3})

Solve

x ln (2) = ln (\frac{7}{3}) : x = \frac{ln ( \frac{7}{3} )}{ln ( 2 )}

x = \frac{ln ( \frac{7}{3} )}{ln ( 2 )}

3^{2 x - 5} + 9^{x - 2} = 4

(\frac{1}{16})^{x} = (\frac{1}{8})^{6}

3^{x + 1} = 81

2^{x} + 2^{x - 1} = 48

e^{2} x - e^{x} = 56

What is the answer to 2^x-1+2^x+2^x+1=7 ?
The answer to 2^x-1+2^x+2^x+1=7 is x=(ln(7/3))/(ln(2))
Solve for x: 2^x-1+2^x+2^x+1=7
The solution is x=(ln(7/3))/(ln(2))