What is the answer to 2^x-2+2^3-x=3 ?

The answer to 2^x-2+2^3-x=3 is No Solution for x\in\mathbb{R}

Solve for x: 2^x-2+2^3-x=3

The solution is No Solution for x\in\mathbb{R}

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2^{x} - 2 + 2^{3} - x = 3

No Solution for x \in R

Solution steps

2^{x} - 2 + 2^{3} - x = 3

Prepare

2^{x} - 2 + 2^{3} - x = 3

for Lambert form:

1 = (x - 3) e^{- l n (2) x}

Rewrite the equation with

(- x + 3) ln (2) = u

and

x = - \frac{u - 3 ln ( 2 )}{ln ( 2 )}

1 = ((- \frac{u - 3 ln ( 2 )}{ln ( 2 )}) - 3) e^{- l n (2) (- \frac{u - 3 l n ( 2 )}{l n ( 2 )})}

Simplify

1 = e^{u - 3 l n (2)} (- \frac{u - 3 ln ( 2 )}{ln ( 2 )} - 3)

Rewrite

1 = e^{u - 3 l n (2)} (- \frac{u - 3 ln ( 2 )}{ln ( 2 )} - 3)

in Lambert form:

e^{u} u = - 8 ln (2)

Solve

e^{u} u = - 8 ln (2) :

No Solution for

u \in R

No Solution for x \in R

5^{b} = 2 5^{b} - 1

2 e^{y} + 15 e^{- y} = 11

2.16 = (1 + 0.12)^{n - 1}

x^{a} = e^{x - 1}

y, \frac{x ^{- 2}}{x ^{y}} = \frac{1}{x ^{12}}

What is the answer to 2^x-2+2^3-x=3 ?
The answer to 2^x-2+2^3-x=3 is No Solution for x\in\mathbb{R}
Solve for x: 2^x-2+2^3-x=3
The solution is No Solution for x\in\mathbb{R}