What are the solutions to the equation x^2-x-6=5 ?

The solutions to the equation x^2-x-6=5 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2

Find the zeros of x^2-x-6=5

The zeros of x^2-x-6=5 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2

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x^{2} - x - 6 = 5

x = \frac{1 + 3 5}{2}, x = \frac{1 - 3 5}{2}

Decimal Notation

x = 3.85410 \dots, x = - 2.85410 \dots

Solution steps

x^{2} - x - 6 = 5

Move

5

to the left side

x^{2} - x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 11) = 35

x_{1, 2} = \frac{- ( - 1 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 3 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 3 5}{2 \cdot 1} : \frac{1 + 3 5}{2}

x = \frac{- ( - 1 ) - 3 5}{2 \cdot 1} : \frac{1 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 3 5}{2}, x = \frac{1 - 3 5}{2}

5 b^{3} - 20 b

36 m^{2} - 84 m + 49 = 0

\frac{2 ^{5}}{2 ^{7}}

1.5 \cdot 3

6 x (3 x - 1)^{2} + 2 x^{2} (1 - 3 x)^{2}

What are the solutions to the equation x^2-x-6=5 ?
The solutions to the equation x^2-x-6=5 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2
Find the zeros of x^2-x-6=5
The zeros of x^2-x-6=5 are x=(1+3sqrt(5))/2 ,x=(1-3sqrt(5))/2