What is the answer to (1/6)^x-13=64 ?

The answer to (1/6)^x-13=64 is x=-(ln(77))/(ln(6))

Solve for x: (1/6)^x-13=64

The solution is x=-(ln(77))/(ln(6))

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(\frac{1}{6})^{x} - 13 = 64

x = - \frac{ln ( 77 )}{ln ( 6 )}

Decimal Notation

x = - 2.42432 \dots

Solution steps

(\frac{1}{6})^{x} - 13 = 64

Move

13

to the right side

(\frac{1}{6})^{x} = 77

Apply exponent rules

x ln (\frac{1}{6}) = ln (77)

Solve

x ln (\frac{1}{6}) = ln (77) : x = - \frac{ln ( 77 )}{ln ( 6 )}

x = - \frac{ln ( 77 )}{ln ( 6 )}

3^{x} = 54

3^{x} = 50

2^{x + 2} + 2^{x} = 2^{2}

3^{a} = - 1

3^{y} + 3^{y} + 2 = \frac{10}{3}

What is the answer to (1/6)^x-13=64 ?
The answer to (1/6)^x-13=64 is x=-(ln(77))/(ln(6))
Solve for x: (1/6)^x-13=64
The solution is x=-(ln(77))/(ln(6))