What is the answer to solvefor a,a^a+5=b^b+a^a-2^2 ?

The answer to solvefor a,a^a+5=b^b+a^a-2^2 is No Solution for a\in\mathbb{R}

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solvefor a,a^a+5=b^b+a^a-2^2

solve for

a, a^{a} + 5 = b^{b} + a^{a} - 2^{2}

No Solution for a \in R

Solution steps

a^{a} + 5 = b^{b} + a^{a} - 2^{2}

Apply exponent rules

e^{a l n (a)} + 5 = b^{b} + e^{a l n (a)} - 2^{2}

Subtract

e^{a l n (a)}

from both sides

e^{a l n (a)} + 5 - e^{a l n (a)} = b^{b} + e^{a l n (a)} - 2^{2} - e^{a l n (a)}

Simplify

5 = b^{b} - 2^{2}

The sides are not equal

No Solution for a \in R

3^{x - 1} - 10 = 17

(2^{x})^{2} = (1 2^{x})^{2}

2^{x + 4} - 2^{x + 3} = 1

p, \frac{a ^{8}}{a ^{p}} = a^{2}

(- 1)^{x} = 0

What is the answer to solvefor a,a^a+5=b^b+a^a-2^2 ?
The answer to solvefor a,a^a+5=b^b+a^a-2^2 is No Solution for a\in\mathbb{R}