What is the answer to 3^y+25=26.2^2+2.3^0 ?

The answer to 3^y+25=26.2^2+2.3^0 is y=(ln(662.44))/(ln(3))

Solve for y: 3^y+25=26.2^2+2.3^0

The solution is y=(ln(662.44))/(ln(3))

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3^{y} + 25 = 26. 2^{2} + 2. 3^{0}

y = \frac{ln ( 662.44 )}{ln ( 3 )}

Decimal Notation

y = 5.91285 \dots

Solution steps

3^{y} + 25 = 26. 2^{2} + 2. 3^{0}

Move

25

to the right side

3^{y} = 26. 2^{2} + 2. 3^{0} - 25

Simplify

3^{y} = 662.44

Apply exponent rules

y ln (3) = ln (662.44)

Solve

y ln (3) = ln (662.44) : y = \frac{ln ( 662.44 )}{ln ( 3 )}

y = \frac{ln ( 662.44 )}{ln ( 3 )}

4^{x} + 2 2^{x} = 12 1^{x}

3^{x} = - 3

3^{x} = 2 7^{x + 2}

3^{x} = - 1

e^{- t} = 0

What is the answer to 3^y+25=26.2^2+2.3^0 ?
The answer to 3^y+25=26.2^2+2.3^0 is y=(ln(662.44))/(ln(3))
Solve for y: 3^y+25=26.2^2+2.3^0
The solution is y=(ln(662.44))/(ln(3))