What is the answer to (1)2^{2x-1}= 1/((8^{x-3))} ?

The answer to (1)2^{2x-1}= 1/((8^{x-3))} is x=2

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(1)2^{2x-1}= 1/((8^{x-3))}

(1) 2^{2 x - 1} = \frac{1}{( 8 ^{x - 3} )}

x = 2

Solution steps

(1) \cdot 2^{2 x - 1} = \frac{1}{( 8 ^{x - 3} )}

Apply exponent rules

2 x - 1 = 3 (- x + 3)

Solve

2 x - 1 = 3 (- x + 3) : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

x, 5 \cdot 1 f \cdot 5^{2 x - 1} - 2 5^{x - 1} = 200

3^{1 - x} - 3^{x} = 2

3^{x} = 14

3^{x} = 12

p = (((1 0^{15})^{2})^{p})^{8} + 4^{3^{2^{0}}}

What is the answer to (1)2^{2x-1}= 1/((8^{x-3))} ?
The answer to (1)2^{2x-1}= 1/((8^{x-3))} is x=2
Solve for x: (1)2^{2x-1}= 1/((8^{x-3))}
The solution is x=2